Title Description:
Read in a positive integer n, calculate the sum of its digits, and write out the sum of each digit in Chinese Pinyin.
Input format:

Each test input contains one test case, i.e. the value of natural number n is given. Here n is guaranteed to be less than 10 100.
Output format:

For each of the digits that output n in a line, there is a space between the Pinyin digits, but there is no space after the last Pinyin digit in a line.
Input sample:

1234567890987654321123456789

Output sample:

yi san wu

Solution:

```import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String n = sc.next();
int sum = 0;
char[] ch = n.toCharArray();
for (int i = 0; i < ch.length; i++) {
sum += (int) (ch[i] - '0');
}
StringBuilder sb = new StringBuilder();
while (sum > 0) {
int a = sum % 10;
switch (a) {
case 0:
sb.append("ling ");
break;
case 1:
sb.append("yi ");
break;
case 2:
sb.append("er ");
break;
case 3:
sb.append("san ");
break;
case 4:
sb.append("si ");
break;
case 5:
sb.append("wu ");
break;
case 6:
sb.append("liu ");
break;
case 7:
sb.append("qi ");
break;
case 8:
sb.append("ba ");
break;
case 9:
sb.append("jiu ");
break;
}
sum /= 10;
}
String s = sb.toString();
String[] sp = s.split(" ");
for (int i = sp.length - 1; i >= 0; i--) {
if (i == 0) System.out.print(sp[i]);
else System.out.print(sp[i] + " ");
}
}

}
```